10=x^2-4x-50

Solution for 10=x^2-4x-50 equation:

10=x^2-4x-50

We move all terms to the left:

10-(x^2-4x-50)=0

We get rid of parentheses

-x^2+4x+50+10=0

We add all the numbers together, and all the variables

-1x^2+4x+60=0

a = -1; b = 4; c = +60;
Δ = b2-4ac
Δ = 42-4·(-1)·60
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-16}{2*-1}=\frac{-20}{-2}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+16}{2*-1}=\frac{12}{-2}
=-6
$